Відео

I was struggling with a problem, and I found I had made a mistake and forgot the distributive property at 4:52 Thank you very much for this, this really helped!

I’ve been trying this method on some few questions and I can’t help but realize it doesn’t work on sum?

You will need to improve your confidence but you have got great potential keep it up and thanks for the lesson. 😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘

it may be 9 years later but this just saved me

how do you get A= 8886?

Thank you so much, know the video is old but appreciate it.

You're assuming that you have the angle and the diagonal length, while it's not realistic. In real world you probably do not have have the diagonal and there's no way to calculate that without having an angle .

Please calculate for me im buying a land. The sides are AB=173, BC=110, CD=138, DA=102

Liked! thank you

This video was made 10 years... But still helps people now

Affg

Thank you!

Very easy to learn, thank you!

I expect to see minus sign on one of the terms in the numerator.

Gorgeous

So is the function open or closed in the voice

Can you have a decimals as answer?

Thanks dude you helped me so much with my homework!

7:32 This is incomprehensible: I'm curious. Where did you exactly get 9 from when there's only 10 marbles in the bag? That makes no sense.

what if both x and y is asked?

rewatching. best video by far

great video

thanks you

Super helpful video, THANK YOU

I can't get the same answers.. what should I do?

you are missing a lot of key points when deriving the GF(general form) to VF(vertex form). Questions like why do we mulitply by one half to the middle term? Well its because, in vertex form, the expression a(x-h)^2+k is = to a(x^2-2ah+h^2). Because, in your GF, a(x^2+b/a(x)+____ does not have 2ah, there we must get the 2 in front of on b/a(x) so we multiply b/a(x) by 2 and get 2b/a(x), but since we just multiply 2 to out of nowhere, we must do divide it by 2. So it would be 2(b/2a)x. Now we have to find h^2, which we know that b/2a is consider H in your general form function, we can square it, therefor (b/2a)^2, since we added an imaginary number the function, we have to subtract it.

This caption is mad

Fascinating. I wonder who thought of this rule first. It certainly isn't first-glance intuitive.

The only video I’ve found with two negative values, thank you so much

Emeklerinize sağlık,Başarılar diliyorum.

When you record audio on a potato

Thank you!

In example number 2, why we should divide both side by 1?

Thank you so much for this.

If there were a Nobel for Clarity this would be on its way to Stockholm..

Here is a difficult limit with a rational number solution. limit (2x^3 + 4/√x - 130 ) / (x - 4) , as x → 4 . The answer is 383/4. See if you can find a way to show that, without using Lhopitals rule.

How to find irregular quadrilateral when only lengths of sides given and angle is not given

Is there any other or easier computation to get/separate, let say for example the 100sqm out of an irregular quadlateral land shape?

UNEMPLOYED?? IN GREENLAND??

Thanks a lot sir , I was having this doubt that why range of sin inverse x is not R , which was Domain of sin x . U cleared my doubt , Thanks

Thank you 9 years later! July 2023

thank you so much this was very well explained!

Amazing explanatin! really helpful, THANKS A LOT!

Thank you bruv . That was clear and on point. 😊

Made it very understandable❤ from South Africa 🇿🇦

sweet

I wish you had shown how lim h->0 of (cosh-1)/h is 0. This confused me and I think in the book _Calculus The Easy Way_ they transposed (cosh-1) andmade it (1-cosh) which is really confusing me. Thank you for your video!

These youtbers do a better job than my teacher

What about with no angle given?

What do you do if the question is asking you to solve for the measure of the angle, but your arcs are given to you as an expression? Like let's say they give you the bigger arc number but they give you the smaller arc like 5×-3